Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) §3.7 Newton’s Method (and Chaos), #37 · Calculus · Applications of derivatives

… is negative at …, positive at …, and negative at the…

This problem is about competitors of Newton.

$f (x) = x^{2} - 4$ is negative at $x = 1$ , positive at $x = 2.5$ , and negative at the midpoint $x = 1.75$ . So $x^{*}$ lies in what interval? Take a second step to cut the interval in half again.

~8 minWritten answer · check your work with Lemma

Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) · §3.7 Newton’s Method (and Chaos), #37

Stuck? A gentle nudge

No hints for this one.

Something off?

Workspace

Your working

Check your full solution

Upload photos of your handwritten work or a PDF, and Lemma will read it and tell you whether it's right — and where it first goes wrong if not.