Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) §13.3 Tangent Planes and Linear Approximations, #43 · Multivariable Calculus · Partial derivatives

Solve … and … by Newton's method from three starting points: …

Solve $g = x^{2} - y^{2} + 1 = 0$ and $h = 2 x y = 0$ by Newton's method from three starting points: $(0, 2)$ and $(- 1, 1)$ and $(2, 0)$ . Take ten steps by computer or one by hand. The solution $(0, 1)$ attracts when $y_{0} > 0$ . If $y_{0} = 0$ you should find the chaos iteration $x_{n + 1} = \frac{1}{2} (x_{n} - x_{n}^{- 1})$ .

~11 minWritten answer · check your work with Lemma

Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) · §13.3 Tangent Planes and Linear Approximations, #43

Stuck? A gentle nudge

No hints for this one.

Something off?

Workspace

Your working

Check your full solution

Upload photos of your handwritten work or a PDF, and Lemma will read it and tell you whether it's right — and where it first goes wrong if not.