The shortest distance from … to the plane … is along the…

The shortest distance from $Q=(2,1,1)$ to the plane $x+y+z=0$ is along the vector ______. The point $\mathbf{P}=Q+t\mathbf{N}=(2+t,1+t,1+t)$ lies on the plane if $t=$ ______. Then $\mathbf{P}=$ ______ and the shortest distance is ______. (This distance is not $|\mathbf{P}|$.)

Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) · §11.2 Planes and Projections, #33