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Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) §10.3 Convergence Tests: All Series, #41 · Calculus · Series

Show that no choice of signs will make … equal to zero

Show that no choice of signs will make $\pm \frac{1}{3} \pm \frac{1}{9} \pm \frac{1}{27} \pm \dots$ equal to zero.

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Gilbert Strang, Calculus, 3rd edition (Wellesley-Cambridge Press; MIT OpenCourseWare RES.18-001) · §10.3 Convergence Tests: All Series, #41

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