#1572 · Algebra · Exponentials & logarithms

Prove an exponential relation

If $a^{3 - x} b^{5 x} = a^{x + 5} b^{3 x}$ , shew that $x lo g (\frac{b}{a}) = lo g a$ .

~8 minProof · checked by AIlogarithmsproof

H. S. Hall & S. R. Knight, Higher Algebra (1891) · Ch. XVI. Logarithms, Examples XVI.a, No. 23

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