Histograms, Frequency Polygons, and Time Series Graphs · Exercise 10

Construct a times series graph for (a) the number of male births, (b) the number of female births, and (c) the total number of births.

$$\begin{array}{cccccccc}\text{Sex/Year}& \text{1855}& \text{1856}& \text{1857}& \text{1858}& \text{1859}& \text{1860}& \text{1861}\\ \text{Female}& \text{45,545}& \text{49,582}& \text{50,257}& \text{50,324}& \text{51,915}& \text{51,220}& \text{52,403}\\ \text{Male}& \text{47,804}& \text{52,239}& \text{53,158}& \text{53,694}& \text{54,628}& \text{54,409}& \text{54,606}\\ \text{Total}& \text{93,349}& \text{101,821}& \text{103,415}& \text{104,018}& \text{106,543}& \text{105,629}& \text{107,009}\end{array}$$

$$\begin{array}{ccccccccc}\text{Sex/Year}& \text{1862}& \text{1863}& \text{1864}& \text{1865}& \text{1866}& \text{1867}& \text{1868}& \text{1869}\\ \text{Female}& \text{51,812}& \text{53,115}& \text{54,959}& \text{54,850}& \text{55,307}& \text{55,527}& \text{56,292}& \text{55,033}\\ \text{Male}& \text{55,257}& \text{56,226}& \text{57,374}& \text{58,220}& \text{58,360}& \text{58,517}& \text{59,222}& \text{58,321}\\ \text{Total}& \text{107,069}& \text{109,341}& \text{112,333}& \text{113,070}& \text{113,667}& \text{114,044}& \text{115,514}& \text{113,354}\end{array}$$

$$\begin{array}{ccccccccc}\text{Sex/Year}& \text{1871}& \text{1870}& \text{1872}& \text{1871}& \text{1872}& \text{1827}& \text{1874}& \text{1875}\\ \text{Female}& \text{56,099}& \text{56,431}& \text{57,472}& \text{56,099}& \text{57,472}& \text{58,233}& \text{60,109}& \text{60,146}\\ \text{Male}& \text{60,029}& \text{58,959}& \text{61,293}& \text{60,029}& \text{61,293}& \text{61,467}& \text{63,602}& \text{63,432}\\ \text{Total}& \text{116,128}& \text{115,390}& \text{118,765}& \text{116,128}& \text{118,765}& \text{119,700}& \text{123,711}& \text{123,578}\end{array}$$

Its source prints no answer for this problem, so there's nothing to check against.

OpenStax, Statistics · §2.2 Histograms, Frequency Polygons, and Time Series Graphs · Exercise 10