OpenStax, Precalculus 2e §3.6 Zeros of Polynomial Functions · Exercise 49 · Algebra · Polynomials

Zeros of Polynomial Functions · Exercise 49

Use Descartes’ Rule to determine the possible number of positive and negative solutions. Then graph to confirm which of those possibilities is the actual combination.

$f (x) = x^{3} - 2 x^{2} + x - 1$

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OpenStax, Precalculus 2e · §3.6 Zeros of Polynomial Functions · Exercise 49

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