Goodness-of-Fit Test · Try It 3

The expected percentage of the number of pets students have in their homes is distributed (this is the given distribution for the student population of the United States) as in.

$$\begin{array}{cc}\text{Number of Pets}& \text{Percent}\\ \text{0}& \text{18}\\ \text{1}& \text{25}\\ \text{2}& \text{30}\\ \text{3}& \text{18}\\ \text{4+}& \text{9}\end{array}$$
A random sample of 1,000 students from the Eastern United States resulted in the data in.

$$\begin{array}{cc}\text{Number of Pets}& \text{Frequency}\\ \text{0}& \text{210}\\ \text{1}& \text{240}\\ \text{2}& \text{320}\\ \text{3}& \text{140}\\ \text{4+}& \text{90}\end{array}$$
At the 1% significance level, does it appear that the distribution “number of pets” of students in the Eastern United States is different from the distribution for the United States student population as a whole? What is the p-value?

Its source prints no answer for this problem, so there's nothing to check against.

OpenStax, Introductory Statistics 2e · §11.2 Goodness-of-Fit Test · Try It 3