#86 · Calculus · The definite integral

The area under a parabola

Long before calculus, this area was known. Show, using a limit of rectangles, that the region under $y = x^{2}$ from $x = 0$ to $x = 1$ has area exactly $\frac{1}{3}$ .

~14 minWritten answer · compare with the solutionRiemann sumsSum of squares

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