It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)), when p=(a+b+c)/2…

It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)), when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 300, 300, and 360 as the side’s lengths, what is the triangle’s area?

This problem repeats another one in the library (at most with different numbers), so it's left out of browsing.

AQuA-RAT — Algebra Question Answering with Rationales (Ling et al., DeepMind, 2017) · train #86403