A is two years older than B who is twice as old…

A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B? Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years. (2x + 2) + 2x + x = 27 5x = 25 x = 5. Hence, B's age = 2x = 10 years.

AQuA-RAT — Algebra Question Answering with Rationales (Ling et al., DeepMind, 2017) · train #63699