It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)), when p=(a+b+c)/2…

It is well known that a triangle’s area is √(p(p-a)(p-b)(p-c)), when p=(a+b+c)/2, such that a, b, c are the lengths of sides of the triangle. If the triangle has 360, 360, and 300 as the side’s lengths, what is the triangle’s area?

AQuA-RAT — Algebra Question Answering with Rationales (Ling et al., DeepMind, 2017) · train #31985